2n P n is equal to

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Other Competitive Exams

NDA

NDA

MATHS

Courses

Class Room Courses
Online Live Courses
Online Recorded Courses

ONLINE COURSES

More

Solution

Q.
${}^{2 n}P_{n}$ is equal to

1 $(n + 1)! \times ({}^{2 n}C_{n})$

2 $n! \times ({}^{2 n}C_{n})$

3 $n! \times ({}^{2 n + 1}C_{n})$

4 $n! \times ({}^{2 n + 1}C_{n + 1})$

Ans.
(2)

${}^{2 n}P_{n} = \frac{(2 n)!}{n!} = n! \times \frac{(2 n)!}{n! n!} = n! \times {}^{2 n}C_{n}$

Want Us to Email you About Special Offers & Updates?