The number of molecules and moles in 2.8375 litres of O 2 at STP are respectively [2023]

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Q.
The number of molecules and moles in $2.8375 litres$ of $O_{2}$ at STP are respectively [2023]

1 $7.527 \times 10^{22}$ and $0.125 mol$

2 $1.505 \times 10^{23}$ and $0.250 mol$

3 $7.527 \times 10^{23}$ and $0.125 mol$

4 $7.527 \times 10^{22}$ and $0.250 mol$

Ans.
(1)

$No. of moles = \frac{Volume at S.T.P (L)}{22.4} = \frac{2.8375}{22.4} = 0.125 mole$

$No. of molecules = no. of moles \times N_{A}$

$= 0.125 \times 6.023 \times 10^{23}$

$= 7.527 \times 10^{22}$

Solution

Q.
The number of molecules and moles in $2.8375 litres$ of $O_{2}$ at STP are respectively [2023]

1 $7.527 \times 10^{22}$ and $0.125 mol$

2 $1.505 \times 10^{23}$ and $0.250 mol$

3 $7.527 \times 10^{23}$ and $0.125 mol$

4 $7.527 \times 10^{22}$ and $0.250 mol$

Ans.
(1)

$No. of moles = \frac{Volume at S.T.P (L)}{22.4} = \frac{2.8375}{22.4} = 0.125 mole$

$No. of molecules = no. of moles \times N_{A}$

$= 0.125 \times 6.023 \times 10^{23}$

$= 7.527 \times 10^{22}$

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Solution

Q. The number of molecules and moles in 2.8375 litres of O2 at STP are respectively [2023]

1 7.527×1022 and 0.125 mol

2 1.505×1023 and 0.250 mol

3 7.527×1023 and 0.125 mol

4 7.527×1022 and 0.250 mol

Ans. (1) No. of moles=Volume at S.T.P (L)22.4=2.837522.4=0.125 mole No. of molecules=no. of moles×NA =0.125×6.023×1023 =7.527×1022

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Q.
The number of molecules and moles in $2.8375 litres$ of $O_{2}$ at STP are respectively [2023]

1 $7.527 \times 10^{22}$ and $0.125 mol$

2 $1.505 \times 10^{23}$ and $0.250 mol$

3 $7.527 \times 10^{23}$ and $0.125 mol$

4 $7.527 \times 10^{22}$ and $0.250 mol$

Ans.
(1)

$No. of moles = \frac{Volume at S.T.P (L)}{22.4} = \frac{2.8375}{22.4} = 0.125 mole$

$No. of molecules = no. of moles \times N_{A}$

$= 0.125 \times 6.023 \times 10^{23}$

$= 7.527 \times 10^{22}$