The equation of the plane passing through the intersection of the planes x + y + z = 6 and 2 x + 3 y + 4 z + 5 = 0 , the point (1, 1, 1) is:

Question

The equation of the plane passing through the intersection of the planes $x + y + z = 6$ and $2 x + 3 y + 4 z + 5 = 0$ , the point (1, 1, 1) is:

Smart Achievers · Accepted Answer

(1)

Ans. $20 x + 23 y + 26 z - 69 = 0$

Explanation:

$(x + y + z - 6) + λ (2 x + 3 y + 4 z + 5) = 0$

$\Rightarrow$ $λ = \frac{3}{14}$

$\Rightarrow$ $20 x + 23 y + 26 z - 69 = 0$

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