If the given planes a x + b y + c z + d = 0 and a ' x + b ' y + c ' z + d ' = 0 be mutually perpendicular, then:

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Solution

Q.
If the given planes $a x + b y + c z + d = 0$ and $a' x + b' y + c' z + d' = 0$ be mutually perpendicular, then:

1 $\frac{a}{a'} = \frac{b}{b'} = \frac{c}{c'}$

2 $\frac{a}{a'} + \frac{b}{b'} + \frac{c}{c'} = 0$

3 $a a' + b b' + c c' + d d' = 0$

4 $a a' + b b' + c c' = 0$

Ans.
(4)

Ans. $a a' + b b' + c c' = 0$

Explanation:

It is a fundamental concept.

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