The charge accumulated on the capacitor connected in the following circuit is ___________ (Given C = 150 )

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Solution

Q.
The charge accumulated on the capacitor connected in the following circuit is ___________ $μ C .$ (Given C = 150 $μ F$ ) [2024]

Ans.
(400)

$V_{A} + \frac{10}{3} (1) - 6 (1) = V_{B}$

$V_{A} - V_{B} = 6 - \frac{10}{3} = \frac{8}{3} volt$

$Q = C (V_{A} - V_{B}) = 150 \times \frac{8}{3} = 400 μ C$

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