In the given figure, the charge stored in capacitor, when points A and B are joined by a connecting wire is

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Solution

Q.
In the given figure, the charge stored in $6 μ F$ capacitor, when points A and B are joined by a connecting wire is ______ $μ C$ [2024]

Ans.
(36)

At steady state, capacitor behaves as an open circuit and current flows in circuit as shown in the diagram.

$R_{eq} = 9 Ω$

$i = \frac{9 V}{9 Ω} = 1 A$

$Δ V_{6 Ω} = 1 \times 6 = 6 V$

$V_{A} = 3 V$

So, potential difference across $6 μ F$ is 6 V.

Hence $Q = C Δ V = 6 \times 6 \times 10^{- 6} C = 36 μ C$

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