Radius ratio of second orbit of and fourth orbit of is . Value of is

Question

Radius ratio of second orbit of $H e^{+}$ and fourth orbit of $B e^{+ 3}$ is $x \times 10^{- 1}$ . Value of $x$ is

Smart Achievers · Accepted Answer

(5)

$\frac{r H e^{+}}{r B e^{3 +}} = \frac{n_{1}^{2}}{z_{1}} \times \frac{z_{2}}{n_{2}^{2}} = \frac{2^{2}}{2} \times \frac{4}{16} = \frac{1}{2} = 0.5 = 5 \times 10^{- 1}$

Solution

Q.
Radius ratio of second orbit of $H e^{+}$ and fourth orbit of $B e^{+ 3}$ is $x \times 10^{- 1}$ . Value of $x$ is

Ans.
(5)

$\frac{r H e^{+}}{r B e^{3 +}} = \frac{n_{1}^{2}}{z_{1}} \times \frac{z_{2}}{n_{2}^{2}} = \frac{2^{2}}{2} \times \frac{4}{16} = \frac{1}{2} = 0.5 = 5 \times 10^{- 1}$

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Solution

Q. Radius ratio of second orbit of He+ and fourth orbit of Be+3 is x×10-1. Value of x is

Ans. (5) rHe+rBe3+=n12z1×z2n22=222×416=12=0.5=5×10-1

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Q.
Radius ratio of second orbit of $H e^{+}$ and fourth orbit of $B e^{+ 3}$ is $x \times 10^{- 1}$ . Value of $x$ is

Ans.
(5)

$\frac{r H e^{+}}{r B e^{3 +}} = \frac{n_{1}^{2}}{z_{1}} \times \frac{z_{2}}{n_{2}^{2}} = \frac{2^{2}}{2} \times \frac{4}{16} = \frac{1}{2} = 0.5 = 5 \times 10^{- 1}$