6 × 10 - 3 mole M 2 O 7 2 - reacts completely with 9 × 10 - 3 mole X n + to give XO 3 - and M 3 + . The value of ' n ' is (M = metal)

Question

$6 \times 10^{- 3}$ mole $M_{2} O_{7}^{2 -}$ reacts completely with $9 \times 10^{- 3}$ mole $X^{n +}$ to give ${XO}_{3}^{-}$ and $M^{3 +} .$ The value of $' n'$ is (M = metal)

Smart Achievers · Accepted Answer

(1)

$M_{2} O_{7}^{2 -} + X^{n +} \to X^{5 +} O_{3}^{-} + M^{3 +}$

$6 \times 10^{- 3} \times 6 = (5 - n) \times 9 \times 10^{- 3} \Rightarrow n = 1$

Solution

Q.
$6 \times 10^{- 3}$ mole $M_{2} O_{7}^{2 -}$ reacts completely with $9 \times 10^{- 3}$ mole $X^{n +}$ to give ${XO}_{3}^{-}$ and $M^{3 +} .$ The value of $' n'$ is (M = metal)

Ans.
(1)

$M_{2} O_{7}^{2 -} + X^{n +} \to X^{5 +} O_{3}^{-} + M^{3 +}$

$6 \times 10^{- 3} \times 6 = (5 - n) \times 9 \times 10^{- 3} \Rightarrow n = 1$

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Solution

Q. 6×10-3 mole M2O72- reacts completely with 9×10-3 mole Xn+ to give XO3- and M3+. The value of 'n' is (M = metal)

Ans. (1) M2O72-+X n+→X5+O3-+M3+ 6×10-3×6=(5-n)×9×10-3⇒n=1

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Q.
$6 \times 10^{- 3}$ mole $M_{2} O_{7}^{2 -}$ reacts completely with $9 \times 10^{- 3}$ mole $X^{n +}$ to give ${XO}_{3}^{-}$ and $M^{3 +} .$ The value of $' n'$ is (M = metal)

Ans.
(1)

$M_{2} O_{7}^{2 -} + X^{n +} \to X^{5 +} O_{3}^{-} + M^{3 +}$

$6 \times 10^{- 3} \times 6 = (5 - n) \times 9 \times 10^{- 3} \Rightarrow n = 1$