Match List - I with List - II, Alcohols, Phenols And Ethers

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Q.
Match List - I with List - II. [2024]

List - I (Reactants) List - II (Products)

(A) Phenol, $Zn / Δ$ (I) Salicylaldehyde

(B) Phenol, ${CHCl}_{3}, NaOH, HCl$ (II) Salicylic acid

(C) Phenol, ${CO}_{2}, NaOH, HCl$ (III) Benzene

(D) $Phenol, Conc . {HNO}_{3}$ (IV) Picric acid

Choose the correct answer from the options given below:

Solution

1 (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

2 (A)-(III), (B)-(I), (C)-(II), (D)-(IV)

3 (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

4 (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Ans.
(2)

(B) This is Reimer-Tiemann formylation reaction

(C) This is Kolbe’s reaction

(D) Nitration of phenol

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	List - I (Reactants)		List - II (Products)
(A)	Phenol, $Zn / Δ$	(I)	Salicylaldehyde
(B)	Phenol, ${CHCl}_{3}, NaOH, HCl$	(II)	Salicylic acid
(C)	Phenol, ${CO}_{2}, NaOH, HCl$	(III)	Benzene
(D)	$Phenol, Conc . {HNO}_{3}$	(IV)	Picric acid

Solution

1 (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

2 (A)-(III), (B)-(I), (C)-(II), (D)-(IV)

3 (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

4 (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Ans. (2) (B) This is Reimer-Tiemann formylation reaction (C) This is Kolbe’s reaction (D) Nitration of phenol

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Ans.
(2)

(B) This is Reimer-Tiemann formylation reaction

(C) This is Kolbe’s reaction

(D) Nitration of phenol