Let P=[3-1-220α3-50], where α∈R. Suppose Q=[qij] is a matrix satisfying PQ=kI3 for some non-zero k∈R. If q23=-k8 and |Q|=k22, then α2+k2 is equal to
(3)
Given that PQ=kI
|P|.|Q|=k3
⇒|P|=2k≠0⇒P is an invertible matrix
∵ PQ=kI ∴Q=kP-1I [∵P-1P=I]
∴ Q=adjP2 ∵ q23=-k8
∴ -(3α+4)2=k8⇒12α+16=k ...(i)
∴ |P|=2k⇒k=10+6α
From (i) and (ii) we get α=-1, k=4
∴ α2+k2=17