Let be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that exactly four girls stand consecutively in the queue. Then the value of m/n is

Question

Let $n$ be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue. Let $m$ be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that exactly four girls stand consecutively in the queue. Then the value of $\frac{m}{n}$ is

Smart Achievers · Accepted Answer

(4)

$m = {}^{6}C_{2} \times {}^{5}C_{4} \times 2! \times 4! \times 5!$

$n = 5! \times 6!$

Solution

1 $\frac{7}{5}$

2 $\frac{5}{2}$

3 $\frac{1}{24}$

4 $5$

Ans.
(4)

$m = {}^{6}C_{2} \times {}^{5}C_{4} \times 2! \times 4! \times 5!$

$n = 5! \times 6!$

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Solution

1 75

2 52

3 124

4 5