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Solution


Q.

The number of ways, of forming a queue of 4 boys and 3 girls such that all the girls are not together, is:          [2026]
1 5040  
2 3050  
3 3410  
4 4320  

Ans.

(4)

Required ways = Total ways of arrangement – All girls together

                         = 7! – 5!×3! = 5040 – 720= 4320