is the time period of a simple pendulum on the earth’s surface. Its time period becomes when taken to a height (equal to earth’s radius) above the earth’s surface. Then, the value of will be [2023]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
$' T'$ is the time period of a simple pendulum on the earth’s surface. Its time period becomes $x T$ when taken to a height $R$ (equal to earth’s radius) above the earth’s surface. Then, the value of $' x'$ will be [2023]

1 $\frac{1}{4}$

2 $4$

3 $\frac{1}{2}$

4 $2$

Ans.
(4)

$T = 2 π \sqrt{\frac{l}{g}}$

$g_{h} = g {(\frac{R}{R + h})}^{2} = g {(\frac{R}{R + R})}^{2} = \frac{g}{4}$

$T \propto \frac{1}{\sqrt{g}} \Rightarrow T' = T \sqrt{\frac{g}{g_{h}}} = 2 T$

Want Us to Email you About Special Offers & Updates?