Choose the correct length versus square of time period graph for a simple pendulum executing simple harmonic motion. [2023]

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Solution

Q.
Choose the correct length $(L)$ versus square of time period $(T^{2})$ graph for a simple pendulum executing simple harmonic motion. [2023]

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Ans.
(3)

$T = 2 π \sqrt{\frac{l}{g}}$

$\Rightarrow T^{2} = \frac{4 π^{2}}{g} \times l$

$\Rightarrow T^{2} \propto l$

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