In the Franck-Hertz experiment, the first dip in the current-voltage graph for hydrogen is observed at 10.2 V. The wavelength of light emitted by the hydrogen atom when excited to the first excitation level is ___ nm.

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Solution

Q.
In the Franck-Hertz experiment, the first dip in the current-voltage graph for hydrogen is observed at 10.2 V. The wavelength of light emitted by the hydrogen atom when excited to the first excitation level is ___ nm.

(Given $h c = 1245 e V n m, e = 1.6 \times 10^{- 19} C$ ) [2024]

Ans.
(122) $10.2 eV = \frac{h c}{λ} \Rightarrow λ = \frac{1245 eV - nm}{10.2 eV} = 122.06 n m$

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