A small object at rest absorbs a light pulse of power 20 mW and duration 300 ns. Assuming speed of light is m/s, the momentum of the object becomes equal to [2023]

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Q.
A small object at rest absorbs a light pulse of power 20 mW and duration 300 ns. Assuming speed of light is $3 \times 10^{8}$ m/s, the momentum of the object becomes equal to [2023]

1 $0.5 \times 10^{- 17}$ kg m/s

2 $2 \times 10^{- 17}$ kg m/s

3 $3 \times 10^{- 17}$ kg m/s

4 $1 \times 10^{- 17}$ kg m/s

Ans.
(2)

$Momentum p = \frac{Energy}{C} = \frac{Power \times time}{C}$

$p = \frac{(20 \times 10^{- 3} W) (300 \times 10^{- 9} s)}{3 \times 10^{8} m/s} = 2 \times 10^{- 17} kg-m/s$

Solution

Q.
A small object at rest absorbs a light pulse of power 20 mW and duration 300 ns. Assuming speed of light is $3 \times 10^{8}$ m/s, the momentum of the object becomes equal to [2023]

1 $0.5 \times 10^{- 17}$ kg m/s

2 $2 \times 10^{- 17}$ kg m/s

3 $3 \times 10^{- 17}$ kg m/s

4 $1 \times 10^{- 17}$ kg m/s

Ans.
(2)

$Momentum p = \frac{Energy}{C} = \frac{Power \times time}{C}$

$p = \frac{(20 \times 10^{- 3} W) (300 \times 10^{- 9} s)}{3 \times 10^{8} m/s} = 2 \times 10^{- 17} kg-m/s$

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Solution

Q. A small object at rest absorbs a light pulse of power 20 mW and duration 300 ns. Assuming speed of light is 3×108m/s, the momentum of the object becomes equal to [2023]

1 0.5×10-17 kg m/s

2 2×10-17 kg m/s

3 3×10-17 kg m/s

4 1×10-17 kg m/s

Ans. (2) Momentum p=EnergyC=Power×timeC p=(20×10-3 W)(300×10-9 s)3×108 m/s=2×10-17 kg-m/s

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Q.
A small object at rest absorbs a light pulse of power 20 mW and duration 300 ns. Assuming speed of light is $3 \times 10^{8}$ m/s, the momentum of the object becomes equal to [2023]

1 $0.5 \times 10^{- 17}$ kg m/s

2 $2 \times 10^{- 17}$ kg m/s

3 $3 \times 10^{- 17}$ kg m/s

4 $1 \times 10^{- 17}$ kg m/s

Ans.
(2)

$Momentum p = \frac{Energy}{C} = \frac{Power \times time}{C}$

$p = \frac{(20 \times 10^{- 3} W) (300 \times 10^{- 9} s)}{3 \times 10^{8} m/s} = 2 \times 10^{- 17} kg-m/s$