Q.

In the expansion of (1+3x+2x2)6, the coefficient of x11 is

1 144  
2 288  
3 216  
4 576  

Ans.

(4)

We have, (1+3x+2x2)6=((1+3x)+(2x2))6

=C06(1+3x)6+C16(1+3x)5 2x2+C26(1+3x)4(2x2)2+C36(1+3x)3(2x2)3+C46(1+3x)2(2x2)4+C56(1+3x)(2x2)5+C66(2x2)6

Coefficient of x11 in above expression is

C56·3·32=6×3×32=576