In alkaline medium, oxidises to

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Solution

Q.
In alkaline medium, ${MnO}_{4}^{-}$ oxidises $I^{-}$ to [2024]

1 ${IO}^{-}$

2 ${IO}_{4}^{-}$

3 $I_{2}$

4 ${IO}_{3}^{-}$

Ans.
(4)

In neutral or faintly alkaline medium, permanganate $({MnO}_{4}^{-})$ oxidizes iodide $(I^{-})$ to iodate $({IO}_{3}^{-})$

$2 {MnO}_{4}^{-} + H_{2} O + I^{-} \to 2 {MnO}_{2} + 2 {OH}^{-} + {IO}_{3}^{-}$

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