The orange colour of and purple colour of is due to

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Q.
The orange colour of $K_{2} {Cr}_{2} O_{7}$ and purple colour of ${KMnO}_{4}$ is due to [2024]

1 Charge transfer transition in both.

2 d → d transitions in ${KMnO}_{4}$ and charge transfer transitions in $K_{2} {Cr}_{2} O_{7}$ .

3 d → d transitions in $K_{2} {Cr}_{2} O_{7}$ and charge transfer transitions in ${KMnO}_{4}$ .

4 d → d transitions in both

Ans.
(1)

A compound is coloured if it has electronic energy levels where electrons can undergo transition by absorbing light in visible range. For most d-block elements, energy difference in d-orbitals lies in visible range. Hence due to d-d electronic transitions, these are coloured. But in $K_{2} {Cr}_{2} O_{7}$ (orange) and ${KMnO}_{4}$ (purple), central atom has no d-electron. Colour of these compounds is due to charge transfer from oxide to metal ion.

Solution

Q.
The orange colour of $K_{2} {Cr}_{2} O_{7}$ and purple colour of ${KMnO}_{4}$ is due to [2024]

1 Charge transfer transition in both.

2 d → d transitions in ${KMnO}_{4}$ and charge transfer transitions in $K_{2} {Cr}_{2} O_{7}$ .

3 d → d transitions in $K_{2} {Cr}_{2} O_{7}$ and charge transfer transitions in ${KMnO}_{4}$ .

4 d → d transitions in both

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Solution

Q. The orange colour of K2Cr2O7 and purple colour of KMnO4 is due to [2024]

1 Charge transfer transition in both.

2 d → d transitions in KMnO4 and charge transfer transitions in K2Cr2O7.

3 d → d transitions in K2Cr2O7 and charge transfer transitions in KMnO4.

4 d → d transitions in both

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Q.
The orange colour of $K_{2} {Cr}_{2} O_{7}$ and purple colour of ${KMnO}_{4}$ is due to [2024]

2 d → d transitions in ${KMnO}_{4}$ and charge transfer transitions in $K_{2} {Cr}_{2} O_{7}$ .

3 d → d transitions in $K_{2} {Cr}_{2} O_{7}$ and charge transfer transitions in ${KMnO}_{4}$ .