If | x - 3 | x - 3 0 , then

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Solution

Q.
If $\frac{| x - 3 |}{x - 3}$ $> 0$ , then

1 $x \in (- 3, \infty)$

2 $x \in (3, \infty)$

3 $x \in (2, \infty)$

4 $x \in (1, \infty)$

Ans.
(2)

Given, $\frac{| x - 3 |}{x - 3}$ $> 0$

$\Rightarrow$ $| x - 3 |$ $> 0 \Rightarrow x - 3 > 0 \Rightarrow x > 3$

$∴$ $x \in (3, \infty)$

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