If U={x:x5-6x4+11x3-6x2=0} and A={x:x2-5x+6=0} and B={x:x2-3x+2=0}, then (A∩B)'=
(3)
∵ U={x:x5-6x4+11x3-6x2=0}={0,1,2,3}
A={x:x2-5x+6=0}={2,3}
and B={x:x2-3x+2=0}={1,2}
∴ A∩B={2}
Hence, (A∩B)'=U-(A∩B)={0,1,2,3}-{2}={0,1,3}