Q.

If x, y, z are real and distinct, then x2+4y2+9z2-6yz-3zx-2xy is always

1 non-negative  
2 non-positive  
3 zero  
4 none of these  

Ans.

(1)

f(x,y,z)=x2+4y2+9z2-6yz-3xz-2xy

=12[2x2+8y2+18z2-12yz-6xz-4xy]

=12[(x-2y)2+(2y-3z)2+(3z-x)2]≥0