If the 10th term of an A.P. is 120 and its 20th term is 110, then the sum of its first 200 terms is
(4)
Given, T10=120=a+9d ...(i)
and T20=110=a+19d ...(ii)
Solving (i) and (ii), we have
a=1200, d=1200
∴ S200=2002[2200+199200]=2012=10012