Q.

If the 10th term of an A.P. is 120 and its 20th term is 110, then the sum of its first 200 terms is

1 5014  
2 100  
3 50  
4 10012  

Ans.

(4)

Given, T10=120=a+9d                        ...(i)

and  T20=110=a+19d                     ...(ii)

Solving (i) and (ii), we have

      a=1200,   d=1200

∴  S200=2002[2200+199200]=2012=10012