If n is the number density and d is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by

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Q.
If $n$ is the number density and $d$ is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by [2024]

Solution

Q.
If $n$ is the number density and $d$ is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by [2024]

1 $\frac{1}{\sqrt{2} n {πd}^{2}}$

2 $\sqrt{2} n {πd}^{2}$

3 $\frac{1}{\sqrt{2 n {πd}^{2}}}$

4 $\frac{1}{\sqrt{2} n^{2} π^{2} d^{2}}$

Ans.
(1)

The mean free path, $λ = \frac{1}{\sqrt{2} n {πd}^{2}}$

$n =$ number of molecules per unit volume,

and $d =$ diameter of the molecule

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Solution

Q. If n is the number density and d is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by [2024]

1 12nπd2

2 2nπd2

3 12nπd2

4 12n2π2d2

Ans. (1) The mean free path, λ=12nπd2 n= number of molecules per unit volume, and d= diameter of the molecule

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Q.
If $n$ is the number density and $d$ is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by [2024]

1 $\frac{1}{\sqrt{2} n {πd}^{2}}$

2 $\sqrt{2} n {πd}^{2}$

3 $\frac{1}{\sqrt{2 n {πd}^{2}}}$

4 $\frac{1}{\sqrt{2} n^{2} π^{2} d^{2}}$

Ans.
(1)

The mean free path, $λ = \frac{1}{\sqrt{2} n {πd}^{2}}$

$n =$ number of molecules per unit volume,

and $d =$ diameter of the molecule