The temperature of a gas having molecules per cubic meter at 1.38 atm is

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Solution

Q.
The temperature of a gas having $2.0 \times 10^{25}$ molecules per cubic meter at 1.38 atm is

(Given, $k = 1.38 \times 10^{- 23} J K^{- 1}$ ) [2024]

1 300 K

2 500 K

3 100 K

4 200 K

Ans.
(2)

ldeal gas equation,

$P V = \frac{N}{N_{A}} R T$

N = Total no. of molecules

$P = \frac{N}{V} k T$

$1.38 \times 1.01 \times 10^{5} = 2 \times 10^{25} \times 1.38 \times 10^{- 23} \times T$

$\Rightarrow T = \frac{1.01 \times 10^{3}}{2} \approx 500 K$

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