If n(A)=4, n(B)=3, n(A×B×C)=24, then n(C)=
(1)
n(A×B×C)=n(A)×n(B)×n(C)
∴ n(C)=n(A×B×C)n(A)×n(B)⇒n(C)=244×3=2
∴ n(C)=2