If n(A) denotes the number of elements in set A and if n(A)=4, n(B)=5 and n(A∩B)=3, then n[(A×B)∩(B×A)]=
(2)
Given n(A)=4, n(B)=5, n(A∩B)=3
n[(A×B)∩(B×A)]=n[(A∩B)×(B∩A)]
=n(A∩B)×n(B∩A)=3×3=9 [∵ n(A×B)=n(A)×n(B)]