Q.

If 2sinα sinβ+3cosβ+5cosα sinβ=38 ∀α,β∈R, then det(adj(adjA)) is equal to (where A=[tanβ-131sinα]) is equal to ______


Ans.

(1)

Let p→=2i^+3j^+5k^;   q→=sinα sinβi^+cosβj^+cosα sinβk^

|q→|=sin2αsin2β+cos2β+cos2αsin2β=1

⇒ sinαsinβ=2λ;  cosβ=3λ;  cosαsinβ=5λ

1=38λ2;  λ=138

detA=[sinα sinβcosβ+13]=1