If 2sinα sinβ+3cosβ+5cosα sinβ=38 ∀α,β∈R, then det(adj(adjA)) is equal to (where A=[tanβ-131sinα]) is equal to ______
(1)
Let p→=2i^+3j^+5k^; q→=sinα sinβi^+cosβj^+cosα sinβk^
|q→|=sin2αsin2β+cos2β+cos2αsin2β=1
⇒ sinαsinβ=2λ; cosβ=3λ; cosαsinβ=5λ
1=38λ2; λ=138
detA=[sinα sinβcosβ+13]=1