If 0<A<B<π, sinA+sinB=32 and cosA+cosB=12, then A is equal to
(1)
Clearly, (sinA+sinB)2+(cosA+cosB)2=2
∴ 2+2(sinA sinB+cosA cosB)=2
⇒cos(B-A)=0⇒B=A+90°
Second equation gives,
cosA-sinA=12
⇒cos(A+45°)=cos60°
∴ A=15°