If cos(α+β)=45 and sin(α-β)=513, where 0≤α, β≤π4, then tan2α is equal to
(2)
cos(α+β)=45
⇒ α+β∈1st quadrant
sin(α-β)=513
⇒ (α-β)∈1st quadrant
Now, 2α=(α+β)+(α-β)
∴ tan2α=tan(α+β)+tan(α-β)1-tan(α+β)tan(α-β)
=34+5121-34·512=56483348=5633