Force between two point charges and placed in vacuum at cm apart is F. Force between them when placed in a medium having dielectric at cm apart will be:

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
Force between two point charges $q_{1}$ and $q_{2}$ placed in vacuum at $' r'$ cm apart is F. Force between them when placed in a medium having dielectric $K = 5$ at $r / 5$ cm apart will be: [2024]

1 F/25

2 5F

3 F/5

4 25F

Ans.
(2)

In air $F = \frac{1}{4 π \in_{0}} \frac{q_{1} q_{2}}{r^{2}}$

In medium

$F' = \frac{1}{4 π (K \in_{0})} \frac{q_{1} q_{2}}{{(r')}^{2}} = \frac{25}{4 π (5 \in_{0})} \frac{q_{1} q_{2}}{{(r)}^{2}} = 5 F$

Want Us to Email you About Special Offers & Updates?