For the given circuit, in the steady state, _______ [2023]

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Solution

Q.
For the given circuit, in the steady state, $| V_{B} - V_{D} |$ $=$ _______ $V.$ [2023]

Ans.
(1)

In steady state, the capacitor behaves as an open circuit. Circuit is:

$\Rightarrow i_{A B} = \frac{6}{3} = 2 A and i_{A D} = \frac{6}{12} = 0.5 A$

$\Rightarrow V_{B} + 2 \times 2 - 10 \times 0.5 = V_{D}$

$\Rightarrow V_{B} - V_{D} = 1 V$

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