For the equilibrium , at a given temperature, rd of AB is dissociated, then will be numerically equal to ................ ( P = Pressure of the mixture at equilibrium)

Question

For the equilibrium ${AB}_{(g)} ⇌ A_{(g)} + B_{(g)}$ , at a given temperature, $\frac{1}{3}$ rd of AB is dissociated, then $\frac{P}{K_{p}}$ will be numerically equal to ................ ( P = Pressure of the mixture at equilibrium)

Smart Achievers · Accepted Answer

(8)

$\begin{matrix} Sol & {AB}_{(g)} & ⇌ & A_{(g)} & + & B_{(g)} \\ to: & 1 & 0 & 0 \\ t_{e q} : & 1 - \frac{1}{3} & \frac{1}{3} & \frac{1}{3} \\ i.e. & \frac{2}{3} & \frac{1}{3} & \frac{1}{3} \end{matrix}$

$∴$ $mole ratio of mixture = 2 : 1 : 1$

$∴$ $K_{p} = \frac{P_{A} P_{B}}{P_{A B}} = \frac{P}{8}$ $∴$ $\frac{P}{K_{p}} = 8$

Solution

Q.
For the equilibrium ${AB}_{(g)} ⇌ A_{(g)} + B_{(g)}$ , at a given temperature, $\frac{1}{3}$ rd of AB is dissociated, then $\frac{P}{K_{p}}$ will be numerically equal to ................ ( P = Pressure of the mixture at equilibrium)

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Solution

Q. For the equilibrium AB(g)⇌A(g)+B(g), at a given temperature, 13rd of AB is dissociated, then PKp will be numerically equal to ................ ( P = Pressure of the mixture at equilibrium)

Ans. (8) SolAB(g)⇌A(g)+B(g)to:100teq:1-131313i.e.231313 ∴ mole ratio of mixture =2:1:1 ∴ Kp=PAPBPAB=P8 ∴ PKp=8

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Q.
For the equilibrium ${AB}_{(g)} ⇌ A_{(g)} + B_{(g)}$ , at a given temperature, $\frac{1}{3}$ rd of AB is dissociated, then $\frac{P}{K_{p}}$ will be numerically equal to ................ ( P = Pressure of the mixture at equilibrium)