Q.

The value of Kc is 64 at 800 K for the reaction N2(g)+3H2(g)⇌2NH3(g).

The value of Kc for the following reaction is:  NH3(g)⇌12N2(g)+32H2(g)

1 8  
2 18  
3 14  
4 164  

Ans.

(2)

N2(g)+3H2(g)⇌2NH3(g); Kc

2NH3(g)⇌N2(g)+3H2(g); 1Kc

Multiplying by 12, reaction becomes

NH3(g)⇌12N2(g)+32H2(g)

∴   New Kc=(1Kc)12=(164)12=18