Find the value of parallelepiped whose edges are represented by a→=2i^-3j^+4k^, b→=i^+2j^-k^, c→=3i^-j^+2k^.
(2)
Ans. 7 cu units
Explanation:
Required volume of parallelepiped =a→·(b→×c→)
a→·(b→×c→)=|2-3412-13-12|
=2(5)+3(5)+4(-7)
=10+15-28=-7
Hence, |a→·(b→×c→)|=|-7|
=7 cu units