If |a→|=3 and |b→|=4, then a value of λ for which a→+λb→ and a→-λb→ are perpendicular is:
(2)
Ans. 34
Explanation:
a→+λb→ is perpendicular to a→-λb→
So, (a→+λb→)·(a→-λb→)=0
|a→|2-λ(a→·b→)+λ(b→·a→)-λ2|b→|2=0
|a→|=3
|b→|=4 (Given)
|a→|2-λ2|b→|2=0
32-λ242=0
λ2=916
λ=±34