Find the magnetic field at the point in figure. The curved portion is a semicircle connected to two long straight wires. [2023]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

Solution

Q.
Find the magnetic field at the point $P$ in figure. The curved portion is a semicircle connected to two long straight wires. [2023]

1 $\frac{μ_{0} i}{2 r} (1 + \frac{2}{π})$

2 $\frac{μ_{0} i}{2 r} (1 + \frac{1}{π})$

3 $\frac{μ_{0} i}{2 r} (\frac{1}{2} + \frac{1}{2 π})$

4 $\frac{μ_{0} i}{2 r} (\frac{1}{2} + \frac{1}{π})$

Ans.
(3)

$B_{P} = (\frac{μ_{0} i}{4 r} + \frac{μ_{0} i}{4 π r}) = \frac{μ_{0} i}{2 r} (\frac{1}{2} + \frac{1}{2 π})$

Want Us to Email you About Special Offers & Updates?

Solution

Q. Find the magnetic field at the point P in figure. The curved portion is a semicircle connected to two long straight wires. [2023]

1 μ0i2r(1+2π)

2 μ0i2r(1+1π)

3 μ0i2r(12+12π)

4 μ0i2r(12+1π)

Ans. (3) BP=(μ0i4r+μ0i4πr)=μ0i2r(12+12π)

Want Us to Email you About Special Offers & Updates?

Q.
Find the magnetic field at the point $P$ in figure. The curved portion is a semicircle connected to two long straight wires. [2023]

1 $\frac{μ_{0} i}{2 r} (1 + \frac{2}{π})$

2 $\frac{μ_{0} i}{2 r} (1 + \frac{1}{π})$

3 $\frac{μ_{0} i}{2 r} (\frac{1}{2} + \frac{1}{2 π})$

4 $\frac{μ_{0} i}{2 r} (\frac{1}{2} + \frac{1}{π})$

Ans.
(3)

$B_{P} = (\frac{μ_{0} i}{4 r} + \frac{μ_{0} i}{4 π r}) = \frac{μ_{0} i}{2 r} (\frac{1}{2} + \frac{1}{2 π})$