Two identical circular wires of radius 20 cm and carrying current are placed in perpendicular planes as shown in the figure. The net magnetic field at the centre of the circular wires is ________ . [2023]

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Solution

Q.
Two identical circular wires of radius 20 cm and carrying current $\sqrt{2} A$ are placed in perpendicular planes as shown in the figure. The net magnetic field at the centre of the circular wires is ________ $\times 10^{- 8} T$ . [2023]

(Take $π = 3.14$ )

Ans.
(628)

$Magnetic field B_{C} at center = \frac{μ_{0} i}{2 r}$

$B_{C} = \frac{4 π \times 10^{- 7}}{2 \times 0.2} \times \sqrt{2} T$

$Net magnetic field is$

$B_{C} \sqrt{2} = \frac{4 π \times 10^{- 7} \times \sqrt{2}}{2 \times 0.2} \times \sqrt{2} T = 2 π \times 10^{- 6} T$

$= 200 π \times 10^{- 8} T = 628 \times 10^{- 8} T$

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