Energy of 10 non rigid diatomic molecules at temperature T is

Question

Energy of 10 non rigid diatomic molecules at temperature T is [2024]

Smart Achievers · Accepted Answer

(1)

Degree of freedom of non-rigid diatomic

$M o l e c u l e s \to f \to R o t a t i o n + T r a n s l a t i o n + V i b r a t i o n$

$↓$ $↓$ $↓$

$2$ $3$ $2$

Degree of freedom, $f = 2 + 3 + 2 = 7$

Energy of one molecule = $\frac{f}{2} K_{B} T$

energy of 10 molecules

$= 10 (\frac{f}{2} K_{B} T) = 10 (\frac{7}{2} K_{B} T) = 35 K_{B} T$

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