Energy of 10 non rigid diatomic molecules at temperature T is

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Solution

Q.
Energy of 10 non rigid diatomic molecules at temperature T is [2024]

1 $35$ $K_{B}$ $T$

2 $35$ $R T$

3 $\frac{7}{2}$ $R T$

4 $70$ $K_{B}$ $T$

Ans.
(1)

Degree of freedom of non-rigid diatomic

$M o l e c u l e s \to f \to R o t a t i o n + T r a n s l a t i o n + V i b r a t i o n$

$↓$    $↓$ $↓$

   $2$ $3$ $2$

  Degree of freedom, $f = 2 + 3 + 2 = 7$

  Energy of one molecule = $\frac{f}{2} K_{B} T$

  energy of 10 molecules

   $= 10 (\frac{f}{2} K_{B} T) = 10 (\frac{7}{2} K_{B} T) = 35 K_{B} T$

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