The average kinetic energy of a monoatomic molecule is 0.414eV at temperature

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Solution

Q.
The average kinetic energy of a monoatomic molecule is 0.414eV at temperature

(Use $K_{B} = 1.38 \times 10^{- 23} J / m o l - K$ ) [2024]

1 3000 K

2 3200 K

3 1600 K

4 1500 K

Ans.
(2)

For monoatomic molecule degree of freedom = 3.

$∴$ $K = \frac{3}{2} K_{B} T$

$T = \frac{0.414 \times 1.6 \times 10^{- 19} \times 2}{3 \times 1.38 \times 10^{- 23}} = 3200 K$

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