∫dxx(x5+3) is equal to:
(2)
Ans. 115log|x5x5+3|+C
Explanation:
Let I=∫dxx(x5+3)
Multiply by x4 in numerator and denominator, we get,
I=∫x4x5(x5+3) dx
Let x5=t
5x4 dx=dt
I=∫15t(t+3) dt
=15×13∫t+3-tt(t+3) dt
=115[∫1t dt-∫1t+3 dt]
=115[logt-log(t+3)]
I=115log|x5x5+3|+C