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Solution


Q.

Consider the following frequency distribution:

Class: 0–6 6–12 12–18 18–24 24–30
Frequency: a b 12 9 5

 

If mean = 30922 and median = 14, then the value of (a−b)2 is equal to _____.
1 2  
2 6  
3 4  
4 8  

Ans.

(3)

N=(26+a+b),    ∑fixi=(504+3a+9b)