Combustion of glucose produces and water. The amount of oxygen (in g) required for the complete combustion of 900g of glucose is:

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Solution

Q.
Combustion of glucose $(C_{6} H_{12} O_{6})$ produces $C O_{2}$ and water. The amount of oxygen (in g) required for the complete combustion of 900g of glucose is: [Molar mass of glucose in g $m o l^{- 1}$ = 180] [2024]

1 480

2 32

3 800

4 960

Ans.
(4)

   $Moles of glucose (n_{C_{6} H_{12} O_{6}}) = \frac{Given mass}{Molar mass}$

   $= \frac{900 g}{180 g {mol}^{- 1}} = 5 mol$

   $C_{6} H_{12} O_{6} (s) + 6 O_{2} (g) \to 6 {CO}_{2} (g) + 6 H_{2} O (l)$

By stoichiometry:

$\frac{n_{O_{2}}}{6} = \frac{n_{C_{6} H_{12} O_{6}}}{1}$

   $\frac{n_{O_{2}}}{6} = \frac{5}{1}$

$n_{O_{2}} = 30 mol$

$W_{O_{2}} = n_{O_{2}} \times M_{O_{2}} = 30 mol \times 32 g m o l^{- 1} = 960 g$

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