10 mL of gaseous hydrocarbon on combustion gives 40 mL of and 50 mL of water vapour. Total number of carbon and hydrogen atoms in the hydrocarbon is

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Solution

Q.
10 mL of gaseous hydrocarbon on combustion gives 40 mL of $C O_{2} (g)$ and 50 mL of water vapour. Total number of carbon and hydrogen atoms in the hydrocarbon is ________ [2024]

Ans.
(14)    $C_{x} H_{y} + (x + \frac{y}{4}) O_{2} \to x {CO}_{2} + (\frac{y}{2}) H_{2} O$

By stoichiometry:

$\frac{V_{C_{x} H_{y}}}{1} = \frac{V_{{CO}_{2}}}{x} = \frac{V_{H_{2} O}}{(\frac{y}{2})}$

   $\frac{10}{1} = \frac{40}{x} = \frac{50}{(\frac{y}{2})}$

   $\Rightarrow x = 4, y = 10$

$The hydrocarbon is C_{4} H_{10} . Total number of carbon and hydrogen atoms in it is 14 .$

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