Binding Energy per nucleon of a fixed nucleus is 6 MeV

Question

Binding Energy per nucleon of a fixed nucleus $X^{A}$ is 6 MeV. It absorbs a neutron moving with KE = 2 MeV, and converts into Y, emitting a photon of energy 1 MeV. The Binding Energy per nucleon of Y (in MeV) is

Smart Achievers · Accepted Answer

(2)

[Because absorption of energy decreases BE and release of energy increases BE] In Y nucleus there are A + 1 nucleons.

$∴$ $\frac{B E}{nucleon} = \frac{6 A - 1}{A + 1}$

Solution

Q.
Binding Energy per nucleon of a fixed nucleus $X^{A}$ is 6 MeV. It absorbs a neutron moving with KE = 2 MeV, and converts into Y, emitting a photon of energy 1 MeV. The Binding Energy per nucleon of Y (in MeV) is

1 $\frac{6 A + 1}{A + 1}$

2 $\frac{6 A - 1}{A + 1}$

3 $7$

4 $\frac{6 A + 1}{A - 1}$

Ans.
(2)

[Because absorption of energy decreases BE and release of energy increases BE] In Y nucleus there are A + 1 nucleons.

$∴$ $\frac{B E}{nucleon} = \frac{6 A - 1}{A + 1}$

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Solution

Q. Binding Energy per nucleon of a fixed nucleus XA is 6 MeV. It absorbs a neutron moving with KE = 2 MeV, and converts into Y, emitting a photon of energy 1 MeV. The Binding Energy per nucleon of Y (in MeV) is

1 6A+1A+1

2 6A-1A+1

3 7

4 6A+1A-1

Ans. (2) [Because absorption of energy decreases BE and release of energy increases BE] In Y nucleus there are A + 1 nucleons. ∴ BEnucleon=6A-1A+1