Assuming the experimental mass of as 12 u, the mass defect of atom is

Question

Assuming the experimental mass of ${}_{6}^{12}C$ as 12 u, the mass defect of ${}_{6}^{12}C$ atom is ______ $MeV / c^{2}$ . (Mass of proton = 1.00727 u, mass of neutron = 1.00866 u, 1 u = 931.5 $MeV / c^{2}$ and $c$ is the speed of the light in vacuum.) [2026]

Smart Achievers · Accepted Answer

(2)

$Δ m = (6 m_{p} + 6 m_{n}) - m_{c}$

$= 6 (1.00727 + 1.00866) - 12$

$= 0.09558 amu = 89.03 MeV / c^{2}$

Solution

Q.
Assuming the experimental mass of ${}_{6}^{12}C$ as 12 u, the mass defect of ${}_{6}^{12}C$ atom is ______ $MeV / c^{2}$ . (Mass of proton = 1.00727 u, mass of neutron = 1.00866 u, 1 u = 931.5 $MeV / c^{2}$ and $c$ is the speed of the light in vacuum.) [2026]

1 127.5

2 89.03

3 272.0

4 92.0

Ans.
(2)

$Δ m = (6 m_{p} + 6 m_{n}) - m_{c}$

$= 6 (1.00727 + 1.00866) - 12$

$= 0.09558 amu = 89.03 MeV / c^{2}$

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