Average force exerted on a non-reflecting surface at normal incidence is . If 360 is the light energy flux during span of 1 hour 30 minutes, Then the area of the surface is

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
Average force exerted on a non-reflecting surface at normal incidence is $2.4 \times 10^{- 4} N$ . If 360 $W . C m^{2}$ is the light energy flux during span of 1 hour 30 minutes, Then the area of the surface is [2024]

1 $0.02$ $m^{2}$

2 $0.2$ $m^{2}$

3 $20$ $m^{2}$

4 $0.1$ $m^{2}$

Ans.
(1)

$Radiation force, F = \frac{I A}{c} \Rightarrow A = \frac{F c}{I}$

$A = \frac{2.4 \times 10^{- 4} \times 3 \times 10^{8}}{360 \times 10^{4}} = \frac{2.4}{120} = 0.02 m^{2}$

Want Us to Email you About Special Offers & Updates?