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Solution


Q.

An alternating voltage source V=260sin(628 t) is connected across a pure inductor of 5 mH. The inductive reactance in the circuit is          [2023]
1 3.14 Ω  
2 6.28 Ω  
3 0.5 Ω  
4 0.318 Ω  

Ans.

(1)

XL=Lω=5 mH×628=3.14 Ω