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Solution


Q.

A bulb and a capacitor are connected in series across an ac supply. A dielectric is then placed between the plates of the capacitor. The glow of the bulb     [2024]
1

increases

 

2

remains same

 

3

becomes zero

 

4

decreases

 


Ans.

(1)       

          As dielectric is placed, capacitance will increase.

            XC=1Cω

           It means the capacitive reactance decreases,so impedance of circuit decreases. Hence current increases. So power increases. So glow of the bulb increases.