Q.

A rod of length 5L is bent right angle keeping one side length as 2L. The position of the centre of mass of the system: (Consider L = 10 cm)          [2025]

1 2i^+3j^  
2 3i^+7j^  
3 5i^+8j^  
4 4i^+9j^  

Ans.

(4)

xcom=2m(10)+3m(0)5m=4 cm

ycom=2m(0)+3m(15)5m=9 cm

rcom=(4i^+9j^) cm