A rod of length 5L is bent right angle keeping one side length as 2L. The position of the centre of mass of the system: (Consider L = 10 cm) [2025]
(4)
xcom=2m(10)+3m(0)5m=4 cm
ycom=2m(0)+3m(15)5m=9 cm
r→com=(4i^+9j^) cm